Transport of cellular glass: trucks

logo_smallIn a previous post, we mentioned that transport of cellular glass over water would be ecologic more logic. But we did not calculate the actual primary energy contribution of transport with trucks compared to the primary energy of the production of cellular glass. We use paper about German truck transport and we assume that the actual load is optimized by using a combination of heavy load and (light) cellular glass to obtain a truck with maximum load. In the best case, we have a fuel consumption of 1.27 l/(ton 100km). We assume that we work with 120 kg/m3 density cellular glass and 1l fuel = 36 MJ. We obtain 1.27 x 120 / 1000 * 36 = 5.5 MJ/(m3 100km). Like already shown in a previous post, the primary energy of GLAPOR ware is 1400 MJ/m3. This means that for a transport to the job site of 500 km, we consume 28 MJ/m3 to compare with the 1400 MJ/m3 during production or 2%. In ecologic thinking, we get the following consequences:

  • One big production line is ecologic better than 10 small production lines distributed over Europe because a big production line is always more efficient. Reduced transport can never compensate this.
  • This plant is best located close to water transport (if not at a canal) because a ship is ecologic better than 32 or even 58 trucks.


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